Question

The mass of $CaCO_3$ produced when carbon dioxide is bubbled through 500 mL of 0.5 M $Ca(OH)_2$ will be

• A. 10 g
• B. 20 g
• C. 50 g
• D. 25 g

Answer 1

Answer: (D)

25 g

Answer 2

$Ca(OH)_{2}+CO_{2} \to CaCO_{3}+H_{2}O$ $Ca(OH)_{2}=0.5\times500\times10^{-3}$ moles $=0.25$ mol Now $1$ mole $Ca(OH)_{2}$ gives $CaCO_{3}=100\,g$ $0.25$ mole $Ca(OH)_{2}$ gives $CaCO_{3}$ $=0.25\times100=25\,g$