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Question

Chemistry Question on Structure of atom

The mass of a photon with wavelength 3.6 ?? 3.6\,?? is:

A

6.135×10−29kg6.135\times {{10}^{-29}}kg

B

3.60×10−29kg3.60\times {{10}^{-29}}kg

C

6.135×10−33kg6.135\times {{10}^{-33}}kg

D

3.60×10−27kg3.60\times {{10}^{-27}}kg

Answer

6.135×10−33kg6.135\times {{10}^{-33}}kg

Explanation

Solution

We know that E=mc2=hcλE =m c^{2}=\frac{h c}{\lambda} ∴λ=hmc\therefore \lambda =\frac{h}{m c} or m=hλc\quad m =\frac{h}{\lambda c} Where, λ=\lambda= wavelength of photon h=h = planck's constant m=m = mass of photon c=c = velocity of light Given, λ=3.6 ??3.6×10−10m\lambda =3.6 \,??3.6 \times 10^{-10} m ∴m=6.62×10−343.6×10−10×3×108\therefore m =\frac{6.62 \times 10^{-34}}{3.6 \times 10^{-10} \times 3 \times 10^{8}} =6.135×10−33kg=6.135 \times 10^{-33} kg