Question

The mass of a lead ball is M. It falls down in a viscous liquid with terminal velocity V. The terminal velocity of another lead ball of mass 8M in the same liquid will be –

• A. 64 V
• B. 4 V
• C. 8 V
• D. V

Answer 1

Answer: (B)

4 V

Answer 2

mass = $\frac{4}{3}$pr³ × r. so when mass become 8M so radius will

become 2r & terminal velocity V_t µ r²

so it becomes 4 times of its previous value.