Question

The mass of ${}_{3}^{7}$ L is $0.042$ amu less than the sum of masses of its constituents. The binding energy per nucleon is

• A. $5.586MeV$
• B. $10.522MeV$
• C. $2.433MeV$
• D. $3.739MeV$

Answer 1

Answer: (A)

$5.586MeV$

Answer 2

: Binding energy, $E_{b}$of ${}_{3}^{7}Li$ $= \Delta m \times 931MeV$

$= 0.042 \times 931MeV$

Binding energy per nucleon

$= \frac{0.042 \times 931}{7} = 5.586MeV$