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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The mass of 112cm3112 \, cm^3 of NH3NH_3 gas at STPSTP is

A

0.085g0.085\, g

B

0.850g0.850\, g

C

8.500g8.500\, g

D

80.500g80.500 \,g

Answer

0.085g0.085\, g

Explanation

Solution

1mol1\, mol of NH3=17g=22400cm3NH _{3}=17\, g =22400 \,cm ^{3} at STP

i.e., 22400cm322400\, cm ^{3} of NH3NH _{3} at STP have mass =17g=17 \,g
112cm3\therefore 112 \,cm ^{3} of NH3NH _{3} at STP will have mass

=1722400×112=0.085g=\frac{17}{22400} \times 112=0.085\, g