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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The mass of 11.2 L of ammonia gas at S.T.P. is

A

8.5 g

B

85 g

C

17 g

D

1.7 g

Answer

8.5 g

Explanation

Solution

Molar mass of NH3=14+3×1=17gmol1NH_{3}=14+3\times1=17\,g\,mol^{-1} \therefore Mass of 22.4L22.4\, L of NH3NH_{3} at S.T.P. =17g= 17 \,g \therefore Mass of 11.2L11.2\,L of NH3NH_{3} at S.T.P.=8.5gS.T.P.=8.5\,g