Question

The mass number of He is 4 and that for sulphur is 32. The radius of sulphur nucleus is larger than that of helium, by times –

• A. $\sqrt{8}$
• B. 4
• C. 2
• D. 8

Answer 1

Answer: (C)

2

Answer 2

r µ (1)^1/3

=

= $\left( \frac { 32 } { 4 } \right) ^ { 1 / 3 }$= (8)^1/3 = 2