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Question: The mass (in g) of \[1{\text{ }}mole{\text{ }}of{\text{ }}{O_2}\] is:...

The mass (in g) of 1 mole of O21{\text{ }}mole{\text{ }}of{\text{ }}{O_2} is:

Explanation

Solution

Hint : We must know that an oxygen molecule is having two oxygen atoms (covalently bonded), and the mass of one atom is 16 amu16{\text{ }}amu.

Complete step by step solution :
First Of all it is important that we understand the meaning of the term molar mass. Molar mass is the mass of one mole of a substance. For example, the mass of one mole of oxygen will be called its molar mass.
Another thing to note is that one molar mass in grams is equivalent to the molecular mass of the substance.
Now coming to Oxygen, we know that one molecule of oxygen carries 2 atoms of oxygen and one mole of oxygen atom is having mass of 16g so,
Oxygen (O2)(O_2)$$; = {\text{ }}16 \times 2{\text{ }} = {\text{ }}32g/molTherefore,wecanstatethatonemoleofoxygencontains Therefore, we can state that one mole of oxygen contains32g.Anotherwaytocalculatemolarmassistousetheformulamentionedbelow:. Another way to calculate molar mass is to use the formula mentioned below: Mass{\text{ }}of{\text{ }}a{\text{ }}substance = {\text{ }}molar{\text{ }}mass{\text{ }} \times {\text{ }}number{\text{ }}of{\text{ }}molesSo,wearehavingmolarmassof So, we are having molar mass of{O_2}equaltoequal to 32gandnumberofmolesisone,nowputtingthisinthegivenweget,Massofsubstanceand number of moles is one, now putting this in the given we get, Mass of substance = {\text{ }}32g{\text{ }}X{\text{ }}1{\text{ }} = {\text{ }}32g$$

Hence, the mass (in g) of1 mole of O2is 32g1{\text{ }}mole{\text{ }}of{\text{ }}{O_2} is {\text{ }}32g

Note : We can use the mole to calculate the number of elementary entities (usually atoms or molecules) in a certain mass of a given substance. Also we know Avogadro’s number is an absolute number: there are 6.022×10236.022 \times {10^{23}} elementary entities in 1 mole. We can also be written as 6.022×1023  mol16.022 \times {10^{23\;}}mo{l^{ - 1}}.The mass of one mole of a substance is equal to that substance’s molecular weight.