Question
Question: The mass and energy equivalent to 1amu are respectively - A. \(1.67\times {{10}^{-27}}gm,9.30MeV\)...
The mass and energy equivalent to 1amu are respectively -
A. 1.67×10−27gm,9.30MeV
B. 1.67×10−27kg,930MeV
C. 1.67×10−27kg,1MeV
D. 1.67×10−34kg,1MeV
Solution
Hint: The standard definition of 1 amu is -
“One twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state”
You can find the value using this definition. Then, you can use the famous mass-energy relation to find the energy equivalent of 1 amu.
Formula Used:
The mass-energy equivalence formula is given by,
E=mc2
Where,
E is the energy equivalent of the mass
m is the mass
c is the speed of light.
Complete step by step solution:
Let’s discuss the standard definition of 1 amu.
It is defined as one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state.
So, we need to find the mass of an C-12 atom and divide it with 12 to find the mass equivalent of 1 amu.
We know that,
Mass of 1 mole C atoms = 12 gms
1 mole C atoms have the following number of atoms-
6.023×1023
Hence, mass of each C-12 atom =
6.023×102312
According to the definition, 1 amu=
121 × Mass of each C-12 atom
=121×6.023×102312
=1.66×10−27kg
Hence, 1 amu =1.66×10−27kg
Now, let’s find the energy equivalent of 1 amu.
We can write the famous mass-energy relation,
E=mc2
Here, mass is, m=1.66×10−27kg
And the speed of light , c=3×108m/s
So, we can write,
E=(1.66×10−27)(3×108)2J
We need to convert Joules into electron volt.
We know the relation between these two quantities -
1eV=1.6×10−19J
Hence, we can write,
E=1.6×10−19(1.66×10−27)(3×108)2eV
E=930MeV
So, energy equivalent of 1 amu is
E=930MeV
So, the correct answer is (B).
Note: The energy equivalence of 1 amu is an important quantity in finding the energy difference in atomic reactions. In atomic reactions, there will always be a mass difference. We can calculate the energy released or absorbed using the mass difference that is expressed in amu units.