Question

The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (if it is a second’s pendulum on earth)

• A. $\frac { 1 } { \sqrt { 2 } }$sec
• B. $2 \sqrt { 2 }$sec
• C. 2 sec
• D. $\frac { 1 } { 2 }$ sec

Answer 1

Answer: (B)

$2 \sqrt { 2 }$sec

Answer 2

$g \propto \frac { M } { R ^ { 2 } }$; $g ^ { \prime } = g / 2$ ;

(T = 2 sec for second’s pendulum)

$T ^ { \prime } = 2 \sqrt { 2 }$