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Question

Question: The marks of \(24\) candidates in the subject mathematics are given below: \[45,48,15,23,30,35,40,...

The marks of 2424 candidates in the subject mathematics are given below:
45,48,15,23,30,35,40,11,29,0,3,12,48,50,18,30,15,30,11,42,23,2,3,4445,48,15,23,30,35,40,11,29,0,3,12,48,50,18,30,15,30,11,42,23,2,3,44
The maximum marks are 5050. Make a frequency distribution taking class intervals 010,1020,........0 - 10,10 - 20,........

Explanation

Solution

Here we will first arrange the numbers in ascending order and then fill them in the specific class interval which is given to us. Finally we get the required answer.

Complete step-by-step solution:
It is given that the question stated as the marks of 2424 students given to us as:
45,48,15,23,30,35,40,11,29,0,3,12,48,50,18,30,15,30,11,42,23,2,3,4445,48,15,23,30,35,40,11,29,0,3,12,48,50,18,30,15,30,11,42,23,2,3,44
Now we have to construct the data as in ascending order.
0,2,3,3,11,11,12,15,15,15,18,23,23,29,30,30,30,35,40,42,44,45,48,48,500,2,3,3,11,11,12,15,15,15,18,23,23,29,30,30,30,35,40,42,44,45,48,48,50
From the question we know that the maximum marks of the test are 5050.
Therefore, the class intervals in which the marks will be put in will be 010,1020,2030,3040,4050.0 - 10,10 - 20,20 - 30,30 - 40,40 - 50. each having a gap of total 1010 marks.
Now in the interval 0100 - 10 the numbers which will be put are: 0,3,2,30,3,2,3
So the total numbers of candidates who have marks in the class interval 0100 - 10 are: 44
Now in the interval 102010 - 20 the numbers which will be put are: 15,11,12,18,15,1115,11,12,18,15,11
So, the total numbers of candidates who have marks in the class interval 102010 - 20 are 66.
Again, in the interval 203020 - 30 the numbers which will be put are: 23,29,2323,29,23
So, the total numbers of candidates who have marks in the class interval 203020 - 30 are 33.
Also, we take the interval 304030 - 40 the numbers which will be put are: 30,35,30,3030,35,30,30
So, the total numbers of candidates who have marks in the class interval 304030 - 40 are 44.
Now in the interval 405040 - 50 the numbers which will be put are: 45,48,40,48,50,42,4445,48,40,48,50,42,44
So, the total numbers of candidates who have marks in the class interval 405040 - 50 are 77.
Therefore, the frequency table could be made as:

Class intervalFrequency
0100 - 1044
102010 - 2066
203020 - 3033
304030 - 4044
405040 - 5077
Total2424

Note: The application of a frequency table is to find the mean, median and mode of grouped data. It is also used to create a cumulative frequency curve also called an ogive.
The frequency table made in the above problem has the class intervals which are continuous.