Question
Question: The marks obtained by \(15\) students of a class test are \(12,14,07,09,23,11,08,13,11,19,16,24,17,0...
The marks obtained by 15 students of a class test are 12,14,07,09,23,11,08,13,11,19,16,24,17,03,20. Find
(i) The mean of their marks.
(ii) The mean of their marks when the marks of each student are increased by 4.
Solution
In this problem, we have given the marks obtained by 15 students of a class test. First we are asked to find the mean of the marks which is obtained by the students of a class test. Next we are asked to find the mean of their marks when the marks of each student are increased by 4. For this we have to add 4 to each given mark.
Formula used: m=number of the studentssum of the marks , where m is the mean.
Complete step by step solution:
Given that, the marks obtained by 15 students of a class test are 12,14,07,09,23,11,08,13,11,19,16,24,17,03,20.
For our convenient let us arrange the marks obtained by 15 students in an ascending order, 03,07,08,09,11,11,12,13,14,16,17,19,20,23,24
(i) Mean of the marks obtained by 15 students of the class test (m)=number of the studentssum of the marks
⇒m=1503+07+08+09+11+11+12+13+14+16+17+19+20+23+24
⇒m=15207, solving this fraction, we get
Hence,
⇒m=13.8
∴ Mean of the marks obtained by 15 students of the class test =13.8
(ii) The new marks after increasing each student mark by 4 are,
07,11,12,13,15,15,16,17,18,20,21,24,23,27,28
Mean of the new marks after increasing each student mark by 4 (m)=number of the studentssum of the marks
⇒m=1507+11+12+13+15+15+16+17+18+20+21+23+24+28
⇒m=15267, solving this fraction, we get
Hence,
⇒m=17.8
∴ Mean of the new marks after increasing each student mark by 4 =17.8
Note: In the first sub division we found the mean value for the given marks obtained by 15 student of the class test. In the second sub division we found the mean value for the student marks when the marks of each student are increased by 4, that is in simple we can add (15×4=)60 to the sum of the marks in the first subdivision.