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Question: The marks obtained by \(15\) students of a class test are \(12,14,07,09,23,11,08,13,11,19,16,24,17,0...

The marks obtained by 1515 students of a class test are 12,14,07,09,23,11,08,13,11,19,16,24,17,03,2012,14,07,09,23,11,08,13,11,19,16,24,17,03,20. Find
(i) The mean of their marks.
(ii) The mean of their marks when the marks of each student are increased by 44.

Explanation

Solution

In this problem, we have given the marks obtained by 1515 students of a class test. First we are asked to find the mean of the marks which is obtained by the students of a class test. Next we are asked to find the mean of their marks when the marks of each student are increased by 44. For this we have to add 44 to each given mark.

Formula used: m=sum of the marks number of the studentsm = \dfrac{{{\text{sum of the marks }}}}{{{\text{number of the students}}}}, where m is the mean.

Complete step by step solution:
Given that, the marks obtained by 1515 students of a class test are 12,14,07,09,23,11,08,13,11,19,16,24,17,03,2012,14,07,09,23,11,08,13,11,19,16,24,17,03,20.
For our convenient let us arrange the marks obtained by 1515 students in an ascending order, 03,07,08,09,11,11,12,13,14,16,17,19,20,23,2403,07,08,09,11,11,12,13,14,16,17,19,20,23,24
(i) Mean of the marks obtained by 1515 students of the class test (m)=sum of the marksnumber of the students(m) = \dfrac{{{\text{sum of the marks}}}}{{{\text{number of the students}}}}
m=03+07+08+09+11+11+12+13+14+16+17+19+20+23+2415\Rightarrow m = \dfrac{{03 + 07 + 08 + 09 + 11 + 11 + 12 + 13 + 14 + 16 + 17 + 19 + 20 + 23 + 24}}{{15}}
m=20715\Rightarrow m = \dfrac{{207}}{{15}}, solving this fraction, we get
Hence,
m=13.8\Rightarrow m = 13.8
\therefore Mean of the marks obtained by 1515 students of the class test =13.8 = 13.8
(ii) The new marks after increasing each student mark by 44 are,
07,11,12,13,15,15,16,17,18,20,21,24,23,27,2807,11,12,13,15,15,16,17,18,20,21,24,23,27,28
Mean of the new marks after increasing each student mark by 44 (m)=sum of the marksnumber of the students(m) = \dfrac{{{\text{sum of the marks}}}}{{{\text{number of the students}}}}
m=07+11+12+13+15+15+16+17+18+20+21+23+24+2815\Rightarrow m = \dfrac{{07 + 11 + 12 + 13 + 15 + 15 + 16 + 17 + 18 + 20 + 21 + 23 + 24 + 28}}{{15}}
m=26715\Rightarrow m = \dfrac{{267}}{{15}}, solving this fraction, we get
Hence,
m=17.8\Rightarrow m = 17.8
\therefore Mean of the new marks after increasing each student mark by 44 =17.8 = 17.8

Note: In the first sub division we found the mean value for the given marks obtained by 1515 student of the class test. In the second sub division we found the mean value for the student marks when the marks of each student are increased by 44, that is in simple we can add (15×4=)60(15 \times 4 = )60 to the sum of the marks in the first subdivision.