Question

The major product $P$ in the following reaction is $C{{H}_{3}}-CH=C{{H}_{2}}\xrightarrow[Peroxide]{HI}P$

• A. $CH _{3} CH _{2} CH _{2} I$
• B. $C{{H}_{3}}-\underset{\text{I}}{{\underset{|}{{CH}}}}-C{{H}_{3}}$
• C. $\underset{\text{I}}{{\underset{|}{{C}}}}{{H}_{2}}-CH=C{{H}_{2}}$
• D. $\underset{\text{I}}{{\underset{|}{\mathop{C}}}}{{H}_{2}}-\underset{\text{I}}{{\underset{|}{{C}}}}{{H}_{2}}$

Answer 1

Answer: (B)

$C{{H}_{3}}-\underset{\text{I}}{{\underset{|}{{CH}}}}-C{{H}_{3}}$

Answer 2

The product of given reaction will be according to Markownikoff's rule, this is because peroxide effect is applicable only in case of $HBr$ and not effective in case of $HI$.
$C{{H}_{3}}-CH=C{{H}_{2}}\xrightarrow[peroxide]{HI}C{{H}_{3}}-\underset{\text{I}}{{\underset{|}{{CH}}}}-C{{H}_{3}}$