Question

The major product of the following reaction is P. Number of oxygen atoms present in product 'P' is _______ (nearest integer).

Answer 1

The reaction proceeds as follows:
Step 1: The triple bond in CH$_3$C$\equiv$C-CH$_3$ is reduced to a trans-alkene using Na/liq. NH$_3$:
$\text{CH}_3\text{C} \equiv \text{C-CH}_3 \xrightarrow{\text{Na/liq. NH}_3} \text{CH}_3\text{CH} = \text{CHCH}_3$
Step 2: The trans-alkene undergoes oxidation with dilute KMnO$_4$ at 273 K. This leads to the formation of a vicinal diol:
$\text{CH}_3\text{CH} = \text{CHCH}_3 \xrightarrow{\text{dil. KMnO}_4} \text{CH}_3\text{CH(OH)CH(OH)CH}_3$
The final product P' contains two hydroxyl (-OH) groups, contributing two oxygen atoms. Number of oxygen atoms in product P':
$2 \, (\text{from hydroxyl groups})$

Answer 2

The reaction proceeds as follows:
Step 1: The triple bond in CH$_3$C$\equiv$C-CH$_3$ is reduced to a trans-alkene using Na/liq. NH$_3$:
$\text{CH}_3\text{C} \equiv \text{C-CH}_3 \xrightarrow{\text{Na/liq. NH}_3} \text{CH}_3\text{CH} = \text{CHCH}_3$
Step 2: The trans-alkene undergoes oxidation with dilute KMnO$_4$ at 273 K. This leads to the formation of a vicinal diol:
$\text{CH}_3\text{CH} = \text{CHCH}_3 \xrightarrow{\text{dil. KMnO}_4} \text{CH}_3\text{CH(OH)CH(OH)CH}_3$
The final product P' contains two hydroxyl (-OH) groups, contributing two oxygen atoms. Number of oxygen atoms in product P':
$2 \, (\text{from hydroxyl groups})$