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Chemistry Question on Alkenes

The major product formed in the following reaction is : CH3CH=CHCH(CH3)2⟶HBrCH _{3} CH = CHCH \left( CH _{3}\right)_{2} \stackrel{ HBr }{\longrightarrow}

A

CH3CH2CH2C(Br)(CH3)2CH _{3} CH _{2} CH _{2} C ( Br )\left( CH _{3}\right)_{2}

B

Br⁡(CH2)3CH(CH3)2\operatorname{Br}\left( CH _{2}\right)_{3} CH \left( CH _{3}\right)_{2}

C

CH3CH2CH(Br)CH(CH3)2CH _{3} CH _{2} CH ( Br ) CH \left( CH _{3}\right)_{2}

D

CH3CH(Br)CH2CH(CH3)2CH _{3} CH ( Br ) CH _{2} CH \left( CH _{3}\right)_{2}

Answer

CH3CH2CH2C(Br)(CH3)2CH _{3} CH _{2} CH _{2} C ( Br )\left( CH _{3}\right)_{2}

Explanation

Solution

Addition of HBr according to M.R.