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Question: The magnitudes of vectors \(\overrightarrow{A},\overrightarrow{B}\)and\(\overrightarrow{C}\)are 3, 4...

The magnitudes of vectors A,B\overrightarrow{A},\overrightarrow{B}andC\overrightarrow{C}are 3, 4 and 5 units respectively. If A+B=C\overrightarrow{A} + \overrightarrow{B} = \overrightarrow{C}, the angle between A\overrightarrow{A}and B\overrightarrow{B}is

A

π2\frac{\pi}{2}

B

cos1(0.6)\cos^{- 1}(0.6)

C

tan1(75)\tan^{- 1}\left( \frac{7}{5} \right)

D

π4\frac{\pi}{4}

Answer

π2\frac{\pi}{2}

Explanation

Solution

C=A2+B2C = \sqrt{A^{2} + B^{2}}

=32+42=5\sqrt{3^{2} + 4^{2}} = 5

\therefore Angle between A\overset{\rightarrow}{A} and B\overset{\rightarrow}{B} is π2\frac{\pi}{2}