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Question: The magnitudes of enthalpy changes for irreversible adiabatic expansion of a gas from 1L to 2L is \(...

The magnitudes of enthalpy changes for irreversible adiabatic expansion of a gas from 1L to 2L is Δ\DeltaH1 and for reversible adiabatic expansion for the same expansion is Δ\DeltaH2. Then

A

Δ\DeltaH1>Δ\DeltaH2

B

Δ\DeltaH1<Δ\DeltaH2

C

Δ\DeltaH1 = Δ\DeltaH2, enthalpy being a state function (Δ\DeltaH1 = Δ\DeltaH2)

D

Δ\DeltaH1 = Δ\DeltaE1&Δ\DeltaH2 = Δ\DeltaE2 where Δ\DeltaE1&Δ\DeltaE2 are magnitudes of change in internal energy of gas in these expansions respectively.

Answer

Δ\DeltaH1<Δ\DeltaH2

Explanation

Solution

|Wrev| > |WIrr|

Tfinal(rev) < Tfinal(Irr)

Δ\DeltaTrev > Δ\DeltaTIrr

\because Δ\DeltaH Δ\propto \DeltaT

Δ\DeltaHrev > Δ\DeltaHIrr