Question

The magnitude of the equatorial magnetic field due to a bar magnet of length 2 cm at a distance of 1 m from its mid-point is (magnetic moment of the bar magnet is $0.60 \mathrm {~A} \mathrm {~m} ^ { 2 }$)

• A. 5.0 x 10-5 T
• B. 6.0xl0-8 T
• C. 7.0 x 10-7 T
• D. 8.0 x 10-8 T

Answer 1

Answer: (B)

6.0xl0-8 T

Answer 2

: Magnetic field of equatorial point is,

Here, and

$\therefore \mathrm { B } _ { \mathrm { E } } = \frac { 10 ^ { - 7 } \times 0.60 } { ( 1 ) ^ { 3 } } = 6.0 \times 10 ^ { - 8 } \mathrm {~T}$