Question

The magnitude of the earth’s magnetic field at a place is $B_{0}$ and the angle of dip is$\delta$. A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is

• A. Zero
• B. $B_{0}lv\sin\delta$
• C. $B_{0}lv$
• D. $B_{0}lv\cos\delta$

Answer 1

Answer: (B)

$B_{0}lv\sin\delta$

Answer 2

When a conductor lying along the magnetic north-south, moves eastwards it will cut vertical component of $B_{0}$. So induced emf

$e = vB_{V}l = v(B_{0}\sin\delta l) = B_{0}lv\sin\delta$.