Solveeit Logo
Login

Question

Question: The magnitude of magnetic moment (spin only) of \(\lbrack NiCl_{4}\rbrack^{2 -}\)will be...

The magnitude of magnetic moment (spin only) of [NiCl4]2−\lbrack NiCl_{4}\rbrack^{2 -}will be

A

2.82B.M.2.82B.M.

B

2.32B.M2.32B.M

C

1.23B.M1.23B.M

D

5.64B.M5.64B.M

Answer

2.82B.M.2.82B.M.

Explanation

Solution

In [NiCl4]2−,\lbrack NiCl_{4}\rbrack^{2 -}, In is in +2 oxidations state.

In [NiCl4]2−\lbrack NiCl_{4}\rbrack^{2 -}

In [NiCl4]2−:4d16∣1∣∣1∣↑∣↑∣↑4s⏟sp34p4s4⏟×x∣×x∣×x\left[ \mathrm { NiCl } _ { 4 } \right] ^ { 2 - } : \frac { 4 d } { 16 | 1 | | 1 | \uparrow | \uparrow | \uparrow } \underbrace { 4 s } _ { s p ^ { 3 } } \frac { 4 p } { 4 s } \underbrace { 4 } _ { \times x | \times x | \times x }

[…. N = number of unpaired electrons]

Magnetic moment , μ=n(n+2)\mu = \sqrt{n(n + 2)}

=2(2+2)=2.82B.M.= \sqrt{2(2 + 2)} = 2.82B.M.