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Question: The magnitude of electric field intensity \(E\) is such that, an electron placed in it would experie...

The magnitude of electric field intensity EE is such that, an electron placed in it would experience an electrical force equal to its weight is given by

A

mgemge

B

mge\frac{mg}{e}

C

emg\frac{e}{mg}

D

e2m2g\frac{e^{2}}{m^{2}}g

Answer

mge\frac{mg}{e}

Explanation

Solution

According to the question,eE=mgeE = mg ⇒ E=mgeE = \frac{mg}{e}