Question

The magnifying power of objective of a compound microscope is 5. If the magnifying power of microscope is 30, then magnifying power of eyepiece will be

• A. 0.17
• B. 6
• C. 3
• D. 25

Answer 1

Answer: (B)

6

Answer 2

Total magnification
$M =M_0 \times M_e$

Given $M = 30$ and $M_0 = 5$
$\Rightarrow M_e =\frac{M}{M_0} = \frac{30}{5} = 6$