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Question: The magnifying power of an astronomical telescope is 8 and the distance between the two lenses is 54...

The magnifying power of an astronomical telescope is 8 and the distance between the two lenses is 54cm. The focal length of eye lens and objective lens will be respectively

A

6 cm and 48 cm

B

48 cm and 6 cm

C

8 cm and 64 cm

D

64 cm and 8 cm

Answer

6 cm and 48 cm

Explanation

Solution

Given that L=54L _ { \infty } = 54

By using m=fofe\left| m _ { \infty } \right| = \frac { f _ { o } } { f _ { e } } and L=fo+feL _ { \infty } = f _ { o } + f _ { e } we get fo=6 cmf _ { o } = 6 \mathrm {~cm}

and fe=48 cmf _ { e } = 48 \mathrm {~cm}.