Solveeit Logo

Question

Question: The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance betwee...

The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance between the objective and the eye-piece is found to be 20 cm. The focal length of the two lenses are

A

18 cm, 2 cm

B

11 cm, 9 cm

C

10 cm, 10 cm

D

15 cm, 5 cm

Answer

18 cm, 2 cm

Explanation

Solution

= 9

fo + fe = 20

fo = 9fe

fe + 9fe = 20

fe = 2cm

fo = 18