Question
Question: The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance betwee...
The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance between the objective and the eye-piece is found to be 20 cm. The focal length of the two lenses are
A
18 cm, 2 cm
B
11 cm, 9 cm
C
10 cm, 10 cm
D
15 cm, 5 cm
Answer
18 cm, 2 cm
Explanation
Solution
= 9
fo + fe = 20
fo = 9fe
fe + 9fe = 20
fe = 2cm
fo = 18