Question

The magnifying power of a telescope is 10 and length of telescope is 1.1 m for normal adjustment. The magnification when image is formed at least distance of distinct vision is –

• A. 14
• B. 6
• C. 16
• D. 18

Answer 1

Answer: (A)

14

Answer 2

10 = & f₀ + f_e

\ f₀ = 1m & f_e = 0.1 m

When final image is at D; then

mp = f₀ = 100 $\left( \frac { 1 } { 25 } + \frac { 1 } { 10 } \right)$= 14