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Question: The magnetic moment of an electron orbiting in a circular orbit of radius r with a speed v is equal ...

The magnetic moment of an electron orbiting in a circular orbit of radius r with a speed v is equal to:

A

evr/2

B

evr

C

er/2v

D

None of these

Answer

evr/2

Explanation

Solution

Magnetic moment μ = niA

Where n = number of turns of the current loop

I = current; Since the orbiting electron behaves as a current loop of current i, we can write

i=eT=e2πrv=ev2πr\mathrm { i } = \frac { \mathrm { e } } { \mathrm { T } } = \frac { \mathrm { e } } { \frac { 2 \pi \mathrm { r } } { \mathrm { v } } } = \frac { \mathrm { ev } } { 2 \pi \mathrm { r } }

A = area of the loop = πr2

μ=(1)(ev2πr)(πr2)\Rightarrow \mu = ( 1 ) \left( \frac { \mathrm { ev } } { 2 \pi \mathrm { r } } \right) \left( \pi \mathrm { r } ^ { 2 } \right) = evr2\frac { \mathrm { evr } } { 2 } .

Hence (1) is correct