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Question

Physics Question on Moving charges and magnetism

The magnetic moment of a magnet of length 10cm10 \,cm and pole strength 4.0Am4.0\, Am will be:

A

0.4Am20.4\,A{{m}^{2}}

B

1.6Am21.6\,A{{m}^{2}}

C

20Am220\,A{{m}^{2}}

D

8.0Am28.0\,A{{m}^{2}}

Answer

0.4Am20.4\,A{{m}^{2}}

Explanation

Solution

The magnetic moment or magnetic dipole moment is a measure of the strength of a magnetic source. The magnetic moment is denned as pole strength multiplied by the distance between the poles,
M=m×2lM=m\times 2l
Given, 2l=10cm=10×102m,m=4Am2l=10\,cm=10\times {{10}^{-2}}m,\,m=4\,A-m
\therefore M=0.10×4=0.4Am2M=0.10\times 4=0.4\,A-{{m}^{2}}
Note: Magnetic moment is a vector quantity pointing along the axis of the magnet from SS to NN.