Question

The magnetic moment of 25Mn in ionic state is B.M, then Mn is in :

• A. +2 state
• B. +3 state
• C. +4 state
• D. +5 state

Answer 1

Answer: (C)

+4 state

Answer 2

$\sqrt{15}$=$\sqrt{n(n + 2)}$ ; n = 3, and three unpaired electrons are found when Mn is in Mn4+ i.e., 3d3 4s0 configuration as its metal electron configuration is [Ar]18 3d5 4s2.