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Question

Physics Question on Magnetic Force

The magnetic force on a point charge is F=q(V×B)\vec{ F }= q (\vec{ V } \times \vec{ B }) Here, q=q= electric charge V=\vec{ V }= velocity of point charge B=\vec{ B }= magnetic Held The dimension of B\vec{B} is :

A

[MLT1A][MLT^{-1}A]

B

[M2LT2A1] [M^{2}LT^{2}A^{-1}]

C

[MT2A1] [MT^{-2}A^{-1}]

D

none of these

Answer

[MT2A1] [MT^{-2}A^{-1}]

Explanation

Solution

F=qv×BF=q \vec{v} \times \vec{B} or F=qvBsinθ[B]=[Fqv]F=q v B \sin \theta[B]=\left[\frac{F}{q v}\right] =[MLT1][AT][LT1]=\frac{\left[M L T^{-1}\right]}{[A T]\left[L T^{-1}\right]} =[MT2A1]=\left[M T^{-2} A^{-1}\right]