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Question: The magnetic force <img src="https://cdn.pureessence.tech/canvas_115.png?top_left_x=1359&top_left_y=...

The magnetic force on a current carrying conductor of length l in an external magnetic field is given by

A
B

I→×B→I\frac { \overrightarrow { \mathrm { I } } \times \overrightarrow { \mathrm { B } } } { \mathrm { I } }

C

I(l→×B→)\mathrm { I } ( \overrightarrow { \mathrm { l } } \times \overrightarrow { \mathrm { B } } )

D
Answer

I(l→×B→)\mathrm { I } ( \overrightarrow { \mathrm { l } } \times \overrightarrow { \mathrm { B } } )

Explanation

Solution