Solveeit Logo

Question

Physics Question on Magnetic Force

The magnetic force acting on a charged particle of charge 2μC-2 \mu C in a magnetic field of 2T2 T acting in y direction, when the particle velocity is is (2i^+3j^)×106ms1 (2 \hat{i} + 3\hat{j}) \times 10^6 \, ms^{-1}

A

4 N in z direction

B

8 N in y direction

C

8 N in z direction

D

8 N in - z direction

Answer

8 N in - z direction

Explanation

Solution

F=q(v×B)\vec{ F } = q (\vec{ v } \times \vec{ B })
=2×106[(2i^+3j^)×106×2j^]=-2 \times 10^{-6}\left[(2 \hat{ i }+3 \hat{ j }) \times 10^{6} \times 2 \hat{ j }\right]
=(8N)k^=-(8 N ) \hat{ k }