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Question

Question: The magnetic flux linked with a coil of *N* turns of area of cross section A held with its plane par...

The magnetic flux linked with a coil of N turns of area of cross section A held with its plane parallel to the field B is

A

B

NAB

C

NAB4\frac { \mathrm { NAB } } { 4 }

D

Zero

Answer

Zero

Explanation

Solution

Magnetic flux linked with a coil

ϕ=NBAcosθ\phi = \mathrm { NBA } \cos \theta

Since the magnetic field B is parallel to the area A,

i.e. θ=90\theta = 90 ^ { \circ }

ϕ=0\therefore \phi = 0