Question

The magnetic flux linked with a coil of $N$ turns of area of cross section $A$ held with its plane parallel to the field $B$ is

• A. $\frac{NAB}{2}$
• B. $NAB$
• C. $\frac{NAB}{4}$
• D. 0

Answer 1

Answer: (D)

0

Answer 2

$\phi=M B A \cos \theta =M B A \cos 190^{\circ}$
$\phi =-M B A$