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Question: The magnetic flux linked with a coil, in webers, is given by the equations\(\varphi = 3t^{2} + 4t + ...

The magnetic flux linked with a coil, in webers, is given by the equationsφ=3t2+4t+9\varphi = 3t^{2} + 4t + 9. Then the magnitude of induced e.m.f. at t = 2 second will be

A

2 volt

B

4 volt

C

8 volt

D

16 volt

Answer

16 volt

Explanation

Solution

e=−dφdt=−ddt(3t2+4t+9)=−(6t+4)e = - \frac{d\varphi}{dt} = - \frac{d}{dt}\left( 3t^{2} + 4t + 9 \right) = - (6t + 4)

e=−[6(2)+4]=−16⇒∣e∣=16 6muvolte = - \left\lbrack 6(2) + 4 \right\rbrack = - 16 \Rightarrow |e| = 16\mspace{6mu} volt