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Question: The magnetic flux linked with a coil at any instant ‘t’ is given by φ = 5t<sup>3</sup> – 100t + 300,...

The magnetic flux linked with a coil at any instant ‘t’ is given by φ = 5t3 – 100t + 300, the e.m.f. induced in the coil at t = 2 second is

A

– 40 V

B

40 V

C

140 V

D

300 V

Answer

40 V

Explanation

Solution

e=−dφdt=−ddt(5t3−100t+300)e = - \frac{d\varphi}{dt} = - \frac{d}{dt}\left( 5t^{3} - 100t + 300 \right)

=−(15t2−100)= - (15t^{2} - 100) at t = 2sec ; e = 40 V