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Physics Question on Electromagnetic waves

The magnetic field of a plane electromagnetic wave is given by B⃗=2×10−8sin⁡(05×103x+15×1011t)j^T\vec{ B }=2 \times 10^{-8} \sin \left(05 \times 10^3 x +15 \times 10^{11} t \right) \hat{ j } T The amplitude of the electric field would be

A

6 Vm−16\, Vm ^{-1} along xx-axis

B

3 Vm−13\, Vm ^{-1} along z-axis

C

6 Vm−16\, Vm ^{-1} along z-axis

D

2×10−8Vm−12 \times 10^{-8} Vm ^{-1} along z-axis

Answer

6 Vm−16\, Vm ^{-1} along z-axis

Explanation

Solution

The correct option is(C): 6 Vm −1 along z-axis.