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Question

Physics Question on Magnetic Field

The magnetic field due to a current in a straight wire segment of length LL at a point on its perpendicular bisector at a distance r(r>>L)r (r >> L)

A

decreases as 1r\frac{1}{r}

B

decreases as 1r2\frac{1}{r^{2}}

C

decreases as 1r3\frac{1}{r^{3}}

D

approaches a finite limit as rr \to \infty

Answer

decreases as 1r2\frac{1}{r^{2}}

Explanation

Solution

By Biot-Savart's law, the magnetic field due to a current carrying wire is
B=μ04πIdlsinθr2B=\frac{\mu_{0}}{4 \pi} \cdot \frac{I d l \sin \theta}{r^{2}}
So, B1r2B \propto \frac{1}{r^{2}}
So, the magnetic field due to current decreases as inverse square of distance of the point of observation.