Question
Question: The magnetic field \(dB\) at a point r meter always from the current element \(Id\vec l\)aligned at ...
The magnetic field dB at a point r meter always from the current element Idlaligned at angle of the θwith respect to the current element is-
A) (4πμ0)(rIdlsinθ)
B) (4πμ0)(r2Idl)
C) (4πμ0)(r2Idlsinθ)
D) (4πμ0)(rIdl)
Solution
Hint
It can be answered with the help of the Biot savart law, because this law gives the value of the dB with the current element Idl.
Complete answer:
According to the biot savart law-
The magnetic field due the small length dlin which the I current flowing the conductor
Then
dB∝I(current flowing in the conductor)
dB∝dl (small length)
dB∝r21 (inverse of the square of the distance of point p from thedl)
And dBα sinθ (sine of the angle made by the dl with point p)
Hence we can say that
dB∝r2Idlsinθ
Or it can be also written as
dB = Kr2Idlsinθ
Where proportionality constant is equal to the 4πμ0
Or numerically it can be written as
K=4πμ0
Hence the biot savart law
dB = (4πμ0)(r2Idlsinθ)
The final answer is given by
dB = (4πμ0)(r2Idlsinθ).
Option (C) is the correct answer.
Note
This law was given by the two scientist biot and savart, they both were two different scientists who gave the value of the dB. The magnetic concept was firstly realized by the Oesterd's; he noticed that the needle of the magnet moved when current was passing from the wire nearer to it. He gave certain ways to find the direction of the magnetic field like a swimmer's rule.