Question

The magnetic engery stored in an inductor of inductance 4μH carrying a current of 2 A is:

• A. 4μJ
• B. 4μJ
• C. 4mJ
• D. 8μJ

Answer 1

Answer: (D)

8μJ

Answer 2

The correct option is (D): 8μJ
Energy = $\frac{1}{2}Li^2$
=$\frac{1}{2}\times4\times10^{-6}\times2^2$
=$8\times10^{-6}$J
Energy=8μJ