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Question: The magnet of a vibration magnetometer is heated so as to reduce its magnetic moment by 30%. The new...

The magnet of a vibration magnetometer is heated so as to reduce its magnetic moment by 30%. The new periodic time of the magnetometer will be
A) Increases by 25%
B) Increases by 36%
C) Decreases by 25%
D) Increases by 36%

Explanation

Solution

A device that is used to measure the direction, strength, and change of a magnetic field on a location (near or on Earth or it can be in space) is known as a magnetometer. Basically, it is used to measure magnetic intensity and fields. The time period of a magnetometer depends basically on
Moment of inertia of the magnet ‘II
External magnetic field ‘HH
Magnetic Moment ‘MM
Consider these points and use the formula for the Time period of vibration of the magnetometer and hence find percentage.

Complete step by step answer:
Step I: Time Period is given by
T = 2πIMB2\pi \sqrt {\dfrac{I}{{MB}}}

Step II: Let T1T_1 be the time period of the magnetometer before heating and T2T_2 be the time period after heating.
And let M1M_1 and M2M_2 be their respective magnetic moments
T1T_1=2πIM1B2\pi \sqrt {\dfrac{I}{{{M_1}B}}} ……(i)
T2T_2= 2πIM2B2\pi \sqrt {\dfrac{I}{{{M_2}B}}} ……(ii)

Step III: Given in the question is
M2=M136%M1{M_2} = {M_1} - 36\% {M_1}
=M136100M1{M_1} - \dfrac{{36}}{{100}}{M_1}
=100M136M1100\dfrac{{100{M_1} - 36{M_1}}}{{100}}
=64100M1\dfrac{{64}}{{100}}{M_1}

Step IV: Dividing (i) and (ii),
T1T2\dfrac{{{T_1}}}{{{T_2}}}= 64M1100M1\sqrt {\dfrac{{64{M_1}}}{{100{M_1}}}}
T1T2\dfrac{{{T_1}}}{{{T_2}}}=810\dfrac{8}{{10}}
T2=1.25T1{T_2} = 1.25{T_1}

Step V: From equation (ii),
T2{T_2}=2πIM2B2\pi \sqrt {\dfrac{I}{{{M_2}B}}} ……(iii)
Substitute value of T2T_2 in equation (iii),
1.25T1=2πIM2B1.25{T_1} = 2\pi \sqrt {\dfrac{I}{{{M_2}B}}} ……(iv)
Step VI: Subtracting (i) from (iv),
1.25T1T1=2πIM2B2πIM2B1.25{T_1} - {T_1} = 2\pi \sqrt {\dfrac{I}{{{M_2}B}}} - 2\pi \sqrt {\dfrac{I}{{{M_2}B}}}
0.25T1=00.25{T_1} = 0

Step VII: Calculating percentage T1T_1=25%.
The new time period for the magnetometer will increase by 25%.

Option A is the correct answer.

Note:
Magnetometers are used for various purposes and they have their application in different fields. They are used in
- Detecting submarines
- to find deposits of iron in different geographical areas
- by treasure hunters to detect the metals deep inside the earth
- These days magnetometers are also used in electronic gadgets like smartphones in order to receive messages from varying magnetic fields by other nearest electromagnets.