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Question

Question: The lowest value of paramagnetism is shows by...

The lowest value of paramagnetism is shows by

A

[Co(CN)6]3\lbrack Co(CN)_{6}\rbrack^{3 -}

B

[Fe(CN6)]3\lbrack Fe(CN_{6})\rbrack^{3 -}

C

[Cr(CN)6]3\lbrack Cr(CN)_{6}\rbrack^{3 -}

D

[Mn(CN)6]3\lbrack Mn(CN)_{6}\rbrack^{3 -}

Answer

[Co(CN)6]3\lbrack Co(CN)_{6}\rbrack^{3 -}

Explanation

Solution

Electronic configurations of Co3+=3d6Co^{3 +} = 3d^{6}

[Co(CN)6]3\lbrack Co(CN)_{6}\rbrack^{3 -}

No. of unpaired electrons = 0.

Hence, shows no paramagnetism.