Solveeit Logo
Login

Question

Physics Question on mechanical properties of fluid

The lower end of a capillary tube of radius r is placed vertically in water then with the rise of water in the capillary heat evolved is

A

+πr2h2dg2J+\frac{\pi r^2h^2dg}{2J}

B

+πr2h2dgJ+\frac{\pi r^2h^2dg}{J}

C

−πr2h2dg2J-\frac{\pi r^2h^2dg}{2J}

D

−πr2h2dgJ-\frac{\pi r^2h^2dg}{J}

Answer

+πr2h2dg2J+\frac{\pi r^2h^2dg}{2J}

Explanation

Solution

Work done = heat evolved (Average force ×\times h) = heat evolved 2πrT cos θ+02=WJ\frac{2 \pi r T \, cos \, \theta + 0}{2} = \frac{W}{J}