Solveeit Logo

Question

Physics Question on Atomic Spectra

The longest wavelength line in the Lyman series of the hydrogen spectrum is

A

949.8? 949.8\,?

B

972.6? 972.6\,?

C

1215.8? 1215.8\,?

D

1025.8? 1025.8\,?

Answer

1215.8? 1215.8\,?

Explanation

Solution

1λRH[1n121n22]\frac{1}{\lambda} R_{H}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]
For longest wavelength in Lyman series,
n1=1,n2=2n_{1}=1, n_{2}=2
1λ=1.09678×107[1(1)21(2)2]\frac{1}{\lambda}=1.09678 \times 10^{7}\left[\frac{1}{(1)^{2}}-\frac{1}{(2)^{2}}\right]
1λ=1.09678×107×34\frac{1}{\lambda}=\frac{1.09678 \times 10^{7} \times 3}{4}
λ=1.2156×107m\therefore \lambda=1.2156 \times 10^{-7} \,m
=1215.6?=1215.6\,?