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Question

Question: The logic behind ‘NOR’ gate is that it gives....

The logic behind ‘NOR’ gate is that it gives.

A

High output when both the inputs are low

B

Low output when both the inputs are low

C

High output when both the inputs are high

D

None of these

Answer

High output when both the inputs are low

Explanation

Solution

The Boolean expression for ‘NOR’ gate is

Y=A+BY = \overline{A + B}

i.e. if A=B=0A = B = 0 (Low), Y=0+0=0ˉ=1Y = \overline{0 + 0} = \bar{0} = 1 (High)