Question
Question: The locus of z satisfying the inequality log<sub>(0.8)</sub> \|z + 1\| \> log<sub>(0.8)</sub> \|z – ...
The locus of z satisfying the inequality log(0.8) |z + 1| > log(0.8) |z – 1|
A
Re (z) > 0
B
Im (z) < 0
C
Re (z) < 0
D
Im (z) > 0
Answer
Re (z) < 0
Explanation
Solution
Sol. |\overset{̶}{Z} + 1| < |\overset{̶}{Z}–1| Ž (x + 1)2 + y2 < (x – 1)2 + y2
Ž 4 × < 0