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Question

Question: The locus of z satisfying the inequality log<sub>(0.8)</sub> \|z + 1\| \> log<sub>(0.8)</sub> \|z – ...

The locus of z satisfying the inequality log(0.8) |z + 1| > log(0.8) |z – 1|

A

Re (z) > 0

B

Im (z) < 0

C

Re (z) < 0

D

Im (z) > 0

Answer

Re (z) < 0

Explanation

Solution

Sol. |\overset{̶}{Z} + 1| < |\overset{̶}{Z}–1| Ž (x + 1)2 + y2 < (x – 1)2 + y2

Ž 4 × < 0