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Question: The locus of the point of intersection of the lines ax sec θ + b y tan θ= a and ax tan θ + by sec θ ...

The locus of the point of intersection of the lines ax sec θ + b y tan θ= a and ax tan θ + by sec θ = b, where θ is the parameter, is

A

A straight line

B

A circle

C

An ellipse

D

A hyperbola

Answer

A hyperbola

Explanation

Solution

Squaring and subtracting, we get

A2x2 – b2y2 = a2 – b2, which is the equation of hyperbola.