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Question: The locus of the midpoint of the line segment joining the focus to a moving point on the parabola y<...

The locus of the midpoint of the line segment joining the focus to a moving point on the parabola y2 = 4ax is another parabola with the directrix

A

x = -a

B

x = -a/2

C

x =0

D

x = a/2

Answer

x =0

Explanation

Solution

α = at2+α26mu,6muβ=2at+026mu6mu2α=at2+a\frac{at^{2} + \alpha}{2}\mspace{6mu},\mspace{6mu}\beta = \frac{2at + 0}{2}\mspace{6mu} \Rightarrow \mspace{6mu} 2\alpha = at^{2} + a, at = β

∴ The locus of y2 = 4a2(xa2)=4b(xb),6mu(b=a2)\frac{4a}{2}\left( x - \frac{a}{2} \right) = 4b(x - b),\mspace{6mu}\left( b = \frac{a}{2} \right)

∴ Directrix is (x – b) + b = 0 or x =0.