Question
Question: The locus of the middle points of chords of hyperbola 3x<sup>2</sup> – 2y<sup>2</sup> + 4x – 6y = 0 ...
The locus of the middle points of chords of hyperbola 3x2 – 2y2 + 4x – 6y = 0 parallel to y = 2x is
A
3x – 4y = 4
B
3y – 4x + 4 = 0
C
4x – 4y = 3
D
3x – 4y = 2
Answer
3x – 4y = 4
Explanation
Solution
Let mid point be (h, k). Equation of a chord whose mid point is (h, k) would be T = S1
or 3xh – 2yk + 2(x + h) – 3(y + k) = 3h2 – 2k2 + 4h – 6k
⇒ x(3k + 2) – y(2k + 3) – 2h + 3k – 3h2 + 2k2 = 0.
It’s slope is 2k+33h+2=2 (given)
⇒ 3h = 4k + 4.
⇒ Required locus is 3x – 4y = 4