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Question: The locus of the middle points of chords of hyperbola 3x<sup>2</sup> – 2y<sup>2</sup> + 4x – 6y = 0 ...

The locus of the middle points of chords of hyperbola 3x2 – 2y2 + 4x – 6y = 0 parallel to y = 2x is

A

3x – 4y = 4

B

3y – 4x + 4 = 0

C

4x – 4y = 3

D

3x – 4y = 2

Answer

3x – 4y = 4

Explanation

Solution

Let mid point be (h, k). Equation of a chord whose mid point is (h, k) would be T = S1

or 3xh – 2yk + 2(x + h) – 3(y + k) = 3h2 – 2k2 + 4h – 6k

⇒ x(3k + 2) – y(2k + 3) – 2h + 3k – 3h2 + 2k2 = 0.

It’s slope is 3h+22k+3=2\frac{3h + 2}{2k + 3} = 2 (given)

⇒ 3h = 4k + 4.

⇒ Required locus is 3x – 4y = 4