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Question: The locus of the foot of the perpendicular drawn from the centre to any tangent to the ellipse x<sup...

The locus of the foot of the perpendicular drawn from the centre to any tangent to the ellipse x2/a2 + y2/b2 = 1 is –

A

A circle

B

An ellipse

C

A hyperbola

D

None of these

Answer

None of these

Explanation

Solution

Equation of any tangent to the ellipse is

y = mx + a2m2+b2\sqrt{a^{2}m^{2} + b^{2}} … (1)

Equation of the line through the centre (0, 0) perpendicular to (1) is

y = (–1/m) x … (2)

Eliminating m from (1) and (2) we get the required locus of the foot of the perpendicular

as y = –x2y\frac{x^{2}}{y} + a2x2y2+b2\sqrt{a^{2}\frac{x^{2}}{y^{2}} + b^{2}}

or (x2 + y2)2 = a2x2 + b2y2.

Which does not represent a circle, an ellipse or a hyperbola.