Question
Question: The locus of the centre of the circle which cuts off intercepts of length \(2 a\) and \(2 b\) from...
The locus of the centre of the circle which cuts off intercepts of length 2a and 2b from x-axis and y-axis respectively, is.
A
x+y=a+b
B
x2+y2=a2+b2
C
x2−y2=a2−b2
D
x2+y2=a2−b2
Answer
x2−y2=a2−b2
Explanation
Solution
2g2−c=2a ….(i)
2f2−c=2b ….(ii)
On squaring (i) and (ii) and then subtracting (ii) from (i), we get
Hence the locus is x2−y2=a2−b2.